Sql学习第一天——SQL 练习题(建表/sql语句)建站知
导读:1建站知识来自Madrid且订单数少于3的消费者,针对这个要求作出以下:建表做题分析以及sql语句的写法,感兴趣的朋友可以参考下seo网站优化营销型网站建设。
题目:来自Madrid且订单数少于3的消费者
建表:
复制代码 代码如下:
set nocount on --当 SET NOCOUNT 为 ON 时,不返回计数(表示受 Transact-SQL 语句影响的行数)。当 SET NOCOUNT 为 OFF 时,返回计数 use SY GO if object_Id('dbo.Orders') is not null drop table dbo.Orders GO if object_Id('dbo.Customers') is not null drop table dbo.Customers GO create table dbo.Customers ( customerid char(5) not null primary key , city varchar(10) not null ); insert into dbo.Customers values('FISSA','Madrid'); insert into dbo.Customers values('FRNDO','Madrid'); insert into dbo.Customers values('KRLOS','Madrid'); insert into dbo.Customers values('MRPHS','Zion'); create table dbo.Orders ( orderid int not null primary key , customerid char(5) null references customers(customerid) ) insert into dbo.Orders values(1,'FRNDO'); insert into dbo.Orders value高端网站建设s(2,'FRNDO'); insert into dbo.Orders values(3,'KRLOS'); insert into dbo.Orders values(4,'KRLOS'); insert into dbo.Orders values(5,'KRLOS'); insert into dbo.Orders values(6,'MRPHS'); insert into dbo.Orders values(7,null);
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复制代码 代码如下:
select customerid as 消费者,count(customerid) as 订单数 from dbo.Orders where customerid in ( select customerid from dbo.Customers where city = 'Madrid') group by customerid having count(customerid) < 3
结果如图所示:--第一次想到的答案,突然发现少了一个来自Madrid的FISSA订单,FISSA订单数量为0,所以在Orders表中没有出现,所以上面的写法会少一个.--推网站seo优化课程翻了上面的答案,又想到了用表的连接,而用内连接出现的情况会和上面的一样,所以我选择了左连接,如下:
复制代码 代码如下:
select C.customerid as 消费者,count(O.customerid) as 订单数 from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid where C.city= 'Madrid' group by C.customerid having count(C.customerid) < 3
结果如图所示:--查询发现是正确的。--分析查看不带条件的左连接
复制代码 代码如下:
select * from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid
复制代码 代码如下:
select * from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid
结果如图所示:--书中给的标准答案是:
复制代码 代码如下:
select C.customerid , count(O.orderid) as numorders from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid where C.city= 'Madrid' group by C.customerid having count(O.orderid) < 3 order by numorders
声明: 本文由我的SEOUC技术文章主页发布于:2023-05-24 ,文章Sql学习第一天——SQL 练习题(建表/sql语句)建站知主要讲述练习题,语句,SQL网站建设源码以及服务器配置搭建相关技术文章。转载请保留链接: https://www.seouc.com/article/web_6733.html